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In effect, the using declaration enters each named member of the base class into the scope of the derived class The base class member is now entered into the set of overloaded instances associated with the name of the member function within the derived class (The using declaration for a member function cannot specify the parameter list, only the member function name This means that if the function is overloaded within the base class, all the overloaded instances are added to the scope of the derived class type We cannot add only one instance of the set of overloaded base class members) Another common misunderstanding of new C++ programmers is the extent to which they may access the protected members of a base class When we write

class Query { public: const vector<location>* locations() const { return &_loc; } // protected: vector<location> _loc; //

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (818 / 1065) [2001-3-29 11:32:13]

we are saying that a class derived from Query may directly access the _loc data member, while the rest of the program must use the public access function What this means, however, is that the derived class has access to the protected _loc data member of its base class subobject The derived class does not have access to the protected members of an independent base class object For example:

bool NameQuery:: compare( const Query *pquery ) { // ok: protected member of its Query subobject int myMatches = _locsize(); // error: has no direct access rights to the // protected member of an independent Query object int itsMatches = pquery->_locsize(); return myMatches == itsMatches; }

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NameQuery has access to the protected members of only one Query class object: its own Query subobject (These protected members are accessed within the derived class through the implicit this pointer [the this pointer is introduced in Section 134]) The immediate solution to the compile-time error is to rewrite the compare() function to make use of the public location() member function:

bool NameQuery:: compare( const Query *pquery ) { // ok: protected member of its Query subobject int myMatches = _locsize(); // ok: use public access method int itsMatches = pquery->locations()->size(); return myMatches == itsMatches; }

The real problem, however, is an incorrect design on our part Because _loc is a member of the Query base class, compare() properly belongs as a member of the Query class, not to the derived NameQuery class Often, member access problems between a derived and base class can be resolved by moving the operation to the class that contains the inaccessible member, as in this case This form of member access constraint does not apply within a class for other objects of its own class For example:

These sensors are utilised on aircraft such as the B-2 Spirit stealth bomber and have reportedly recently been tted to the F-22 Raptor. See Figure 6.15 for angle of attack and Figure 6.16 for angle of sideslip measurement con gurations.

Diamonds provide another measuring technique that is reliable, but they are a rare occurrence. Most times they are considered a topping pattern, sort of like a head-and-shoulders top. They rarely show up as bottom patterns, but

bool NameQuery:: compare( const NameQuery *pname ) { int myMatches = _locsize(); // ok int itsMatches = pname->_locsize(); // ok as well return myMatches == itsMatches;

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (819 / 1065) [2001-3-29 11:32:13]

A constant pointer to a constant object is defined by combining the two previous definitions For example:

const double pi = 314159; const double *const pi_ptr = π

In this case, neither the value of the object addressed by pi_ptr nor the address itself can be changed (We can read its definition from right to left as " pi_ptr is a constant pointer to an object of type double defined as const")

(a) int i; (d) int *const cpi; (b) const int ic; (e) const int *const cpic; (c) const int *pic;

(a) int i = -1;

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (104 / 1065) [2001-3-29 11:32:03]

(b) (c) (d) (e)

const int ic = i; const int *pic = ⁣ int *const cpi = ⁣ const int *const cpic = ⁣

DIFFERENTIAL OUTPUTS: (P 1 P 2) (P3 P4)

Based on the definitions in the previous exercise, which of the following assignments are legal Explain why

Wedge measurement. (Source: FutureSource. Reprinted with permission.)

(a) i = ic; (b) pic = ⁣ (c) cpi = pic;

(d) pic = cpic; (e) cpic = ⁣ (f) ic = *cpic;

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